A particle is projected with a speed 10 2 m s - 1 and at an angle 45 ° with the horizontal. The rate of change of speed with respect to time at t = 1 s is g = 10 m s - 2

Question

A particle is projected with a speed 10 2 m s - 1 and at an angle 45 ° with the horizontal. The rate of change of speed with respect to time at t = 1 s is g = 10 m s - 2, 10 2 m s - 2, 10 m s - 2, zero, 5 m s - 2

MARKS App · Accepted Answer

At t = 1 s , the particle is at maximum height. At maximum height velocity is horizontal and acceleration is vertical. Hence, the angle between the velocity vector and acceleration vector is 90 ° . Therefore at this position tangential acceleration, i.e., the rate of change of speed with respect to time is zero.

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