A particle is projected with a speed v at 45 ° with the horizontal. The magnitude of angular momentum of the projectille about the point of projection when the particle is at its maximum height h is

Question

A particle is projected with a speed v at 45 ° with the horizontal. The magnitude of angular momentum of the projectille about the point of projection when the particle is at its maximum height h is, Zero, m v h 2 2, m v 2 h 2, m v h 2

MARKS App · Accepted Answer

When a particle is projected with a speed v at 45 ° with the horizontal then velocity of the projectile at maximum height. v ′ = v cos ⁡ 45 ° = v 2 Angular momentum of the projectile about the point of projection = m v ′ h = m v 2 h = m v h 2

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