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A particle is suspended from a vertical spring which is executing S.H.M. of frequency $5 \mathrm{~Hz}$. The spring is unstretched at the highest point of oscillation. Maximum speed of the particle is $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
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$\frac{1}{\pi} \mathrm{m} / \mathrm{s}$
Amplitude of SHM, A $=\frac{\mathrm{mg}}{\mathrm{k}}=\frac{\mathrm{g}}{\omega^2}$
$\omega=2 \pi \mathrm{f}=2 \pi \times 5=10 \pi$
$\begin{aligned} & \therefore \mathrm{A}=\frac{10}{100 \pi^2}=\frac{1}{10 \pi^2} \\ & \mathrm{~V}_{\max }=\mathrm{A} \omega=\frac{1}{10 \pi^2} \times 10 \pi=\frac{1}{\pi} \mathrm{m} / \mathrm{s}\end{aligned}$
$\omega=2 \pi \mathrm{f}=2 \pi \times 5=10 \pi$
$\begin{aligned} & \therefore \mathrm{A}=\frac{10}{100 \pi^2}=\frac{1}{10 \pi^2} \\ & \mathrm{~V}_{\max }=\mathrm{A} \omega=\frac{1}{10 \pi^2} \times 10 \pi=\frac{1}{\pi} \mathrm{m} / \mathrm{s}\end{aligned}$
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