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A particle moves along a circular path with decreasing speed. Hence
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the direction of angular momentum remains constant.
A particle moves along a circular path with speed, then the angular momentum is given by
$\overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{r}} \times \mathrm{m} \overrightarrow{\mathrm{v}}$
When the speed v decrease, the magnitude of of angular momentum decreases. But the direction of angular momentum remains constant.
$\overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{r}} \times \mathrm{m} \overrightarrow{\mathrm{v}}$
When the speed v decrease, the magnitude of of angular momentum decreases. But the direction of angular momentum remains constant.
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