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Question: Answered & Verified by Expert

A particle moves in the x-y plane under the action of a force F such that the coordinates of its linear momentum P at any time t is px=2 cos t,py= 2sint
The angel θ between F and P at a given time t will be

PhysicsCenter of Mass Momentum and CollisionJEE Main
Options:
  • A 90°
  • B 0°
  • C 180°
  • D 30°
Solution:
2528 Upvotes Verified Answer
The correct answer is: 90°
P=px2+py2

=2cost2+2sint2=2

If m be the mass of the body, then kinetic energy

=p22m=222m=2m

Since kinetic energy does not change with time, both work done and power are zero

Now Power = Fvcosθ=0

As F0,v0

 cosθ=0

Or θ=90°

As direction of p is same that v(p=mv) hence angle between F and p is equal to 90°

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