A particle moves so that its acceleration a is given by a = - bx , where x is displacement from equilibrium position and b is a non-negative real constant. The time period of oscillation of the particle is

Question

A particle moves so that its acceleration a is given by a = - bx , where x is displacement from equilibrium position and b is a non-negative real constant. The time period of oscillation of the particle is, 2 π b, 2 π b, 2 π b, 2 π b

MARKS App · Accepted Answer

The relation between acceleration ( a ) and displacement ( x ) for a body in SHM is a = - ω 2 x Given, a = - bx On comparing the two equations, we get ω 2 = b ∴ ω = b Since, ω = 2 π T ∴ 2 π T = b ⇒ T = 2 π b

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