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Question: Answered & Verified by Expert
A particle moves with a velocity 5i^-3j^+6k^m s-1 under the influence of a constant force F=10i^-10j^+20k^N. The instantaneous power applied to the particle is
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Options:
  • A 140 W
     
  • B 40 W
     
  • C 200 W
     
  • D 170 W
     
Solution:
1901 Upvotes Verified Answer
The correct answer is: 200 W
 
v=5i^-3j^+6k^m s-1

F=10i^-10j^+20k^N

Power=F·v=10i^-10j^+20k^·5i^-3j^+6k^

                  = 50 + 30 + 120 = 200 W

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