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A particle moves with a velocity $6 \hat{i}-4 \hat{j}+3 \hat{k} m / s$ under the influence of a constant force $\hat{F}=20 \hat{i}+15 \hat{j}-5 \hat{k} N$. The instantaneous power applied to the particle is
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The correct answer is:
$45 \mathrm{~J} / \mathrm{s}$
$P=\vec{F} \cdot \vec{v}=20 \times 6+15 \times(-4)+(-5) \times 3$
$=120-60-15=120-75=45 \mathrm{~J} / \mathrm{s}$
$=120-60-15=120-75=45 \mathrm{~J} / \mathrm{s}$
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