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Question: Answered & Verified by Expert
A particle moves with a velocity of 4i^2j^+2k^ m s-1 under the influence of a constant force F=10i^+3j^-2k^ N. The instantaneous power applied to the particle is 
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Solution:
1768 Upvotes Verified Answer
The correct answer is: 30
P=Fv

=4i^-2j^+2k^·10i^+3j^-2k^ =40-6-4

P=30 W

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