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Question: Answered & Verified by Expert
A particle of charge q and mass m is moving with a velocity -vi^(v0) towards a large screen placed in the Y-Z plane at distance d. If there is magnetic field B=B0k^, the minimum value of v for which the particle will not hit the screen is :
PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2020 (06 Sep Shift 1)
Options:
  • A qdB03m
  • B 2qdB0m
  • C qdB0m
  • D qdB02m
Solution:
1931 Upvotes Verified Answer
The correct answer is: qdB0m

  

The radius of circular path in given magnetic field is

r=d=mvqB0

so v=qB0dm

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