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Question: Answered & Verified by Expert

A particle of mass 1 mg and charge q is lying at the mid-point of two stationary particles kept at a distance 2 m when each is carrying same charge q. If the free charged particle is displaced from its equilibrium position through distance x x<<1 m. The particle executes SHM. Its angular frequency of oscillation will be _______ ×105 rad s-1 (if q2=10C2)

PhysicsElectrostaticsJEE MainJEE Main 2021 (25 Jul Shift 1)
Solution:
2009 Upvotes Verified Answer
The correct answer is: 6000

Net force on free charged particle, 

F=kq2d+x2-kq2d-x2

F=-kq24dxd2-x22

a=-4kq2dmxd4

a=-4kq2md3x

So, angular frequency 

ω=4 kq2md3

ω=4×9×109×101×10-6×13

ω=6×108 rad sec-1

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