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A particle of mass $1 \mathrm{mg}$ has the same wavelength as an electron moving with a velocity of $3 \times 10^6 \mathrm{~ms}^{-1}$. The velocity of the particle is (mass of electron $=9.1 \times 10^{-31} \mathrm{~kg}$ )
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Verified Answer
The correct answer is:
$2.7 \times 10^{-18} \mathrm{~ms}^{-1}$
Same momentum of both particles
$$
\begin{aligned}
& 1 \times 10^{-3} \times v=9 \times 10^{-31} \times 3 \times 10^6 \\
& v=2.7 \times 10^{-18} \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
$$
\begin{aligned}
& 1 \times 10^{-3} \times v=9 \times 10^{-31} \times 3 \times 10^6 \\
& v=2.7 \times 10^{-18} \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
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