A particle of mass 2 kg is initially at rest. A force starts acting on it in one direction whose magnitude changes with time. The force-time graph is shown in the figure. Find the velocity of the particle at the end of 10 s .

Question

A particle of mass 2 kg is initially at rest. A force starts acting on it in one direction whose magnitude changes with time. The force-time graph is shown in the figure. Find the velocity of the particle at the end of 10 s ., 45 m s − 1, 50 m s − 1, 40 m s − 1, 60 m s − 1

MARKS App · Accepted Answer

Using impulse = change in linear momentum (or area under F - t graph) We have, m(v f – v i ) = Area or 2 v f - 0 = 1 2 × 2 × 1 0 + 2 × 1 0 + 1 2 × 2 × 1 0 + 2 0 + 1 2 × 4 × 2 0 = 1 0 + 2 0 + 3 0 + 4 0 or 2 v f = 1 0 0 or v f = 5 0 m s - 1

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