A particle of mass 20 g is released with an initial velocity 5 m s - 1 along the curve from the point A , as shown in the figure. The point A is at height h from point B . The particle slides along the frictionless surface. When the particle reaches point B , its angular momentum about O will be: (Take g = 10 m s - 2 )

Question

A particle of mass 20 g is released with an initial velocity 5 m s - 1 along the curve from the point A , as shown in the figure. The point A is at height h from point B . The particle slides along the frictionless surface. When the particle reaches point B , its angular momentum about O will be: (Take g = 10 m s - 2 ), 3 kg m 2 s - 1, 2 kg m 2 s - 1, 6 kg m 2 s - 1, 8 kg m 2 s - 1

MARKS App · Accepted Answer

Applying conservation of energy, m g h = 1 2 m v B 2 - 1 2 m v A 2 ⇒ v B = 2 g h + v A 2 ⇒ v B = 2 × 10 × 10 + 25 ⇒ v B = 15 m s - 1 Angular momentum about O , L O = m v B h + a ⇒ L O = 20 × 10 - 3 × 15 × 20 kg m 2 s - 1 ⇒ L O = 6 kg m 2 s - 1

Search any question & find its solution

Looking for more such questions to practice?