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Question: Answered & Verified by Expert

A particle of mass m1 is fastened to one end of a string and another particle of mass m2 is attached to the middle point, the other end of the string being fastened to a fixed point on a smooth horizontal table. If the particles are made to revolve in a horizontal circular path as shown in the figure, then the ratio of tension in the part of the string between the centre and m2 to the tension in the part of the string between m2 and m1 is

PhysicsLaws of MotionJEE Main
Options:
  • A m1m1+m2
  • B m1+m2m1
  • C 2m1+m22m1
  • D 2m1m1+m2
Solution:
2060 Upvotes Verified Answer
The correct answer is: 2m1+m22m1






for m1,

        T1=m1ω22r ......(i)

for m2,

       T2-T1=m2ω2r ....(ii)

Dividing both the equations:

T1T2-T1=2m1m2

T2T1=2m1+m22m1

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