Search any question & find its solution
Question:
Answered & Verified by Expert
A particle of mass $m_1$ is moving with a velocity $v_1$ and another particle of mass $m_2$ is moving with a velocity $v_2$. Both of them have the same momentum but their different kinetic energies are $E_1$ and $E_2$ respectively. If $m_1>m_2$ then:
Options:
Solution:
1141 Upvotes
Verified Answer
The correct answer is:
$E_1 < E_2$
We know that K.E. $=\frac{P^2}{2 m}$
$$
\begin{array}{ll}
\therefore & \frac{E_1}{E_2}=\frac{P_1^2 / 2 m_1}{P_2^2 / 2 m_2} \\
\Rightarrow \quad \frac{E_1}{E_2}=\frac{m_2}{m_1}
\end{array}
$$
Here $\quad m_1=m_2$
$$
\therefore \quad E_1 < E_2
$$
$$
\begin{array}{ll}
\therefore & \frac{E_1}{E_2}=\frac{P_1^2 / 2 m_1}{P_2^2 / 2 m_2} \\
\Rightarrow \quad \frac{E_1}{E_2}=\frac{m_2}{m_1}
\end{array}
$$
Here $\quad m_1=m_2$
$$
\therefore \quad E_1 < E_2
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.