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A particle of mass $m$ and charge $q$ moves with a constant velocity $v$ along the positive $x$-direction. It enters a region containing a uniform magnetic field $B$ directed along the negative $z$ direction, extending from $x=a$ to $x=b$. The minimum value of $v$ required so that the particle can just enter the region $x>b$ is
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The correct answer is:
$q(b-a) B / m$
$\begin{aligned} r= & \frac{m v}{q B}=b-a \\ & (\text { for just entering) } \\ v & =\frac{q(b-a) B}{m}\end{aligned}$


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