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Question: Answered & Verified by Expert
A particle of mass $m$ is attached to three identical massless springs of spring constant ' $k$ ' as shown in the figure. The time period of vertical oscillation of the particle is

PhysicsOscillationsWBJEEWBJEE 2010
Options:
  • A $2 \pi \sqrt{\frac{m}{k}}$
  • B $2 \pi \sqrt{\frac{m}{2 k}}$
  • C $2 \pi \sqrt{\frac{m}{3 k}}$
  • D $\pi \sqrt{\frac{m}{k}}$
Solution:
1858 Upvotes Verified Answer
The correct answer is: $2 \pi \sqrt{\frac{m}{2 k}}$
$$
\begin{aligned}
& \text { Hints : } \mathrm{T}=2 \pi \sqrt{\frac{m}{\mathrm{~K}_{\mathrm{eq}}}} \\
& \mathrm{F}=\mathrm{K} x+2 \mathrm{~K} x \cos ^2 45 \\
& \mathrm{~K}_{\mathrm{eq}} x=\mathrm{K} x+\mathrm{K} x \\
& \mathrm{~K}_{\mathrm{eq}}=2 \mathrm{~K}
\end{aligned}
$$

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