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Question: Answered & Verified by Expert
A particle of mass m is moving along the x-axis under the potential  V(x)= k x 2 2 + λ x  where k and  x are positive constants of appropriate dimensions. The particle is slightly displaced from its equilibrium position. The particle oscillates with the angular frequency ω given by
PhysicsOscillationsNEET
Options:
  • A 3km
  • B 3mk
  • C km
  • D 3mk
Solution:
1479 Upvotes Verified Answer
The correct answer is: km
Given, V(x)= k x 2 2 + λ x

F=-V(x)x= -kx

a=-kmx

ω2=km

ω=km

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