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Question: Answered & Verified by Expert
A particle of mass m is performing the linear simple harmonic motion. Its equilibrium is at x=0, force constant is K and amplitude of SHM is A. The maximum power supplied by the restoring force to the particle during SHM will be:
PhysicsOscillationsJEE Main
Options:
  • A K32A2m
  • B 2K32A2m
  • C K32A23m
  • D K32A22m
Solution:
1355 Upvotes Verified Answer
The correct answer is: K32A22m
Power supplied by the restoring force F=Kx is:
P=FV
P=KxwA2-x2
P=KKmA2x2-x4
P will be max when dpdx=0
A22x-4x3=0
x=A2
Pmax=P|atx=A2=KKmA2A22-A24
Pmax=K32A22m

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