A particle of mass m is released from height h on a smooth curved surface which ends into a vertical loop of radius r , as shown. If h = 2 r , then

Question

A particle of mass m is released from height h on a smooth curved surface which ends into a vertical loop of radius r , as shown. If h = 2 r , then, the particle reaches the top of the loop with zero velocity, the particle reaches the top of the loop with a non-zero velocity, the particle breaks off at a height h = r from base, the particle breaks off at a height r h 2 r

MARKS App · Accepted Answer

To reach the top of loop, particle must have a minimum speed of v = 5 g r at the bottom of the loop. but v 2 = 2 g h = 4 g r , so the block won't reach the highest point of the track.

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