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A particle of mass $m$ is rotating in a plane in circularpath of radius $r$. Its angular momentum is $L$. The centripetal force acting on the particle is
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The correct answer is:
$\frac{L^{2}}{m r^{3}}$
Centripetal force, $F=\frac{m v^{2}}{r}=\frac{m}{r} \frac{L^{2}}{m^{2} r^{2}}=\frac{L^{2}}{m r^{3}}$
$\left[\right.$ As $\left.L=m v r \therefore v=\frac{L}{m r}\right]$
$\left[\right.$ As $\left.L=m v r \therefore v=\frac{L}{m r}\right]$
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