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Question: Answered & Verified by Expert
A particle of mass m moves along the quarter section of the circular path whose centre is at the origin. The radius of the circular path is a. A force F=yi^-xj^ N acts on the particle where xy denote the coordinates of the position of the particle. Calculate the work done by this force, in taking the particle from point A (a,0)  to point B (0, a), along the circular path.

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Options:
  • A -2 a2 J
  • B -π a2 J
  • C -a2 J
  • D -π a22 J
Solution:
2764 Upvotes Verified Answer
The correct answer is: -π a22 J
The given tangential force opposite to the motion

F¯t=x2+y2=a

w=Ftdscos180o -ads=-a.πa2=-πa22 J

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