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Question: Answered & Verified by Expert
A particle of mass \( m \) moves in a circular orbit in a central potential field \( U(r)=\frac{1}{2} k r^{2} . \) If Bohr's quantization conditions are applied, radii of possible orbitals and energy levels vary with quantum number \( n \) as:
PhysicsAtomic PhysicsJEE Main
Options:
  • A \( r_{n} \propto n^{2}, E_{n} \propto \frac{1}{n^{2}} \)
  • B \( r_{n} \propto \sqrt{n}, E_{n} \propto n \)
  • C \( r_{n} \propto n, E_{n} \propto n \)
  • D \( r_{n} \propto \sqrt{n}, E_{n} \propto \frac{1}{n} \)
Solution:
1682 Upvotes Verified Answer
The correct answer is: \( r_{n} \propto \sqrt{n}, E_{n} \propto n \)
Fr=-dUdr=-kr
For circular motion
|Fr|=kr=mv2rkr2=mv2 ........(i)
Bohr's quantization mvr=nh2π ....(ii)
From (i) and (ii)
m2v2m=kr2
1mnh2πr2=kr2n2h24π2mk=r4
r=h24π2mk1/4 n1/2
rn
From equation (i) Un
KE=12mv2PE=12kr2
E=K+U=12mv2+12kr2=kr2n

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