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Question: Answered & Verified by Expert
A particle of mass $m$ moves in the $X Y$ plane with a velocity $v$ along the straight line $\mathrm{AB}$. If the angular momentum of the particle with respect to origin $\mathrm{O}$ is $L_A$ when it is at A and $L_B$ when it is at B, then:

PhysicsRotational MotionJEE Main
Options:
  • A $L_A=L_B$
  • B the relationship between $L_A$ and $L_B$ depends upon the slope of the line $\mathrm{AB}$
  • C $L_A < L_B$
  • D $L_A>L_{B^*}$
Solution:
1114 Upvotes Verified Answer
The correct answer is: $L_A=L_B$
Moment of Momentum is angular momentum. OP is the same whether the mass is at $\mathrm{A}$ or $\mathrm{B}$

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