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A particle of mass $m$ moves in the $X Y$ plane with a velocity $v$ along the straight line $\mathrm{AB}$. If the angular momentum of the particle with respect to origin $\mathrm{O}$ is $L_A$ when it is at A and $L_B$ when it is at B, then:

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The correct answer is:
$L_A=L_B$
Moment of Momentum is angular momentum. OP is the same whether the mass is at $\mathrm{A}$ or $\mathrm{B}$


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