A particle performs SHM with an amplitude of 5 m . If at x = 4 m , the magnitude of velocity and acceleration are equal, then the time period of SHM (in seconds) is

Question

A particle performs SHM with an amplitude of 5 m . If at x = 4 m , the magnitude of velocity and acceleration are equal, then the time period of SHM (in seconds) is, 2 π 3, 4 π 3, 8 π 3, 6 π 3

MARKS App · Accepted Answer

v = ω 5 2 - 4 2 = 3 ω a = ω 2 × 4 a = v 4 ω 2 = 3 ω ω = 3 4 = 2 π T T = 8 π 3 s

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