A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S 1 and that covered in the first 20 seconds is S 2 , then:

Question

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S 1 and that covered in the first 20 seconds is S 2 , then:, S 2 = 3 S 1, S 2 = 4 S 1, S 2 = S 1, S 2 = 2 S 1

MARKS App · Accepted Answer

Given: u = 0 , t 1 = 10 s , t 2 = 20 s Using the relation, S = u t + 1 2 a t 2 Acceleration being the same in two cases. S 1 = 1 2 a × t 1 2 , S 2 = 1 2 a × t 2 2 ∴ S 1 S 2 = ( t 1 t 2 ) 2 = ( 10 20 ) 2 = 1 4 S 2 = 4 S 1

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