A particle starts oscillating simple harmonically from its equilibrium position with time period T . The ratio of KE and PE of the particle at the t = T / 12 is

Question

A particle starts oscillating simple harmonically from its equilibrium position with time period T . The ratio of KE and PE of the particle at the t = T / 12 is, 1 : 4, 2 : 1, 3 : 1, 4 : 1

MARKS App · Accepted Answer

When t = T 12 , t h e n x = A sin ⁡ 2 π T × T 12 = A 2 K E = 1 2 m v 2 = 1 2 m ω 2 ( A 2 - x 2 ) = 1 2 m ω 2 A 2 - A 2 4 = 3 4 1 2 m ω 2 A 2 P E = 1 2 m ω 2 x 2 = 1 4 1 2 m ω 2 A 2 K E P E = 3 1

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