A particle undergoes a one-dimensional motion such that its velocity varies according to v x = β x - 2 n , where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x is given by

Question

A particle undergoes a one-dimensional motion such that its velocity varies according to v x = β x - 2 n , where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x is given by, - 2 n β 2 x - 2 n - 1, - 2 n β 2 x - 4 n - 1, - 2 n β 2 x - 2 n + 1, - 2 n β 2 x - 4 n + 1

MARKS App · Accepted Answer

According to the question a = v d v d x = v d d x β x​ -2 n = - 2 n β x -2 n - 1 β x - 2 n = - 2 n β 2 x - 4 n - 1

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