A particular hydrogen like atom has its ground state binding energy = 122.4 eV . It is in ground state. Then,

Question

A particular hydrogen like atom has its ground state binding energy = 122.4 eV . It is in ground state. Then,, its atomic number is 5, an electron of 90 eV can excite it, an electron of kinetic energy 45.9 eV can be brought to almost rest by this atom, an electron of kinetic energy nearly 2.6 eV may emerge from the atom when electron of kinetic energy 125 eV collides with this atom

MARKS App · Accepted Answer

Ground state binding energy = 13.6 × z 2 eV ⇒ z = 122.4 13.6 = 3 The first excitation energy Δ E = 13.6 × z 2 × 1 - 1 4 eV = 91.8 eV K .E max = 125 − 122.4 = 2.6 eV Hence, 90 eV electron cannot excite it.

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