Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A pendulum is oscillating with an angular amplitude of 90° as shown in the figure. The value of angle α, made by the string with the vertical, at which the acceleration is directed horizontally is

PhysicsRotational MotionJEE Main
Options:
  • A 0
  • B 90°
  • C cos-113
  • D sin-113
Solution:
1028 Upvotes Verified Answer
The correct answer is: cos-113
For horizontal acceleration, net force in vertical direction should be zero.



Loss in potential energy = gain in kinetic energy

mgh=12mv2

mglcosα=12mv2

 v=2glcosα

The net force towards O is

T-mgcosα=mv2l

=m2glcosα l=2 mgcosα

T=3mgcosα

Tcosα=mg

Or 3mg cos2 α=mg

α=cos-113

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.