A pendulum of length 1 m is released from θ = 60 ° . The rate of change of speed of the bob, at θ = 30 ° , is ( g = 10 m s - 2 )

Question

A pendulum of length 1 m is released from θ = 60 ° . The rate of change of speed of the bob, at θ = 30 ° , is ( g = 10 m s - 2 ), 10 m s - 2, 7.5 m s - 2, 5 m s - 2, 5 3 m s - 2

MARKS App · Accepted Answer

When the string makes an angle of 30 ° with the vertical, the component of weight produces the tangential acceleration which is the rate of change of speed a t = g sin 30 ° = 5 m s - 2

Search any question & find its solution

Looking for more such questions to practice?