Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A pendulum of length 10 cm is hanged by a wall making an angle 3° with vertical. It is swung to position B. Time period of pendulum will be

PhysicsOscillationsNEET
Options:
  • A π5  s
  • B 2π15 s
  • C π6 s
  • D subsequent motion will not be periodic
Solution:
1260 Upvotes Verified Answer
The correct answer is: 2π15 s


Let T=2πlg

T=2π0.110=π5 s

Time taken by the pendulum in going from A to B=T4

Time taken by the pendulum in going from B to C=T12

 The time period of the pendulum =2T4+T12=2T3=23.π5=2π15 s

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.