Search any question & find its solution
Question:
Answered & Verified by Expert
A person moved from $A$ to $B$ on a circular path as shown in figure. If the distance travelled by him is $60 \mathrm{~m}$, then the magnitude of displacement would be: $\left(\right.$ Given $\left.\cos 135^{\circ}=-0.7\right)$
Options:
Solution:
2733 Upvotes
Verified Answer
The correct answer is:
$47 \mathrm{~m}$
$\begin{aligned} & \text { Distance travelled }=60 \mathrm{~m} \\ & \Rightarrow \text { Angle covered }=135^{\circ} \\ & \text { Displacement }=2 \mathrm{R} \sin \left(135^{\circ} / 2\right) \\ & =2\left(\frac{60}{135} \times \frac{180}{\pi}\right)\left[\frac{1-\cos \left(135^{\circ}\right)}{2}\right]^{1 / 2} \\ & =2\left(\frac{80}{\pi}\right)(0.85)^{1 / 2} \\ & \approx 47 \mathrm{~m}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.