Search any question & find its solution
Question:
Answered & Verified by Expert
A person of mass $60 \mathrm{~kg}$ is inside a lift of mass $940 \mathrm{~kg}$ and presses the button on control panel. The lift starts moving upwards with an acceleration $1.0 \mathrm{~m} / \mathrm{s}^2$. If $g=10 \mathrm{~m} / \mathrm{s}^2$, the tension in the supporting cable is
Options:
Solution:
1768 Upvotes
Verified Answer
The correct answer is:
$11000 \mathrm{~N}$
$$
\begin{aligned}
& \text { Total mass }=\text { Mass of lift }+ \text { Mass of person } \\
& =940+60=1000 \mathrm{~kg} \\
& T-m g=m a \\
& \text { Hence, } T-1000 \times 10=1000 \times 1 \\
& T=11000 \mathrm{~N} \\
&
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.