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A person starts his journey from centre ' $O$ ' of the park and comes back to the same position following path OPQO as shown in the figure. The radius of path taken by the person is $200 \mathrm{~m}$ and he takes $3 \mathrm{~min} 58 \mathrm{sec}$ to complete his journey. The average speed of the person is $\qquad$ $\mathrm{ms}^{-1} \cdot($ take $\pi=3.14)$
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$3 \mathrm{~m} / \mathrm{s}$
$\begin{aligned} & V_{a v}=\frac{S_{\text {total }}}{T_{\text {total }}}=\frac{200+200+\frac{2 \pi \times 200}{4}}{238} \\ & =\frac{400+100 \pi}{238}=\frac{714}{238}=3 \mathrm{~m} / \mathrm{s}\end{aligned}$
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