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A person walks $25.0^{\circ}$ north of east for $3.18 \mathrm{~km}$. How far would she have to walk due north and then due east to arrive at the same location?
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The correct answer is:
towards north $1.34 \mathrm{~km}$ and towards east $2.88 \mathrm{~km}$
$\therefore \frac{\mathrm{P}}{3.18}=\sin 25^{\circ}$
$\mathrm{P}=3.18 \mathrm{sin} 25^{\circ}$
$=1.34 \mathrm{KM} \rightarrow$ along north
$\mathrm{B}=3.18 \mathrm{cos} 25^{\circ}$
$=2.88 \mathrm{KM} \rightarrow$ along east
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