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Question: Answered & Verified by Expert
A person with vibrating tuning fork of frequency $338 \mathrm{~Hz}$ is moving towards a vertical wall with a speed of $2 \mathrm{~ms}^{-1}$. Velocity of sound in air is $340 \mathrm{~ms}^{-1}$. The number of beats heard by that person per second is
PhysicsWaves and SoundKCETKCET 2013
Options:
  • A 2
  • B 4
  • C 6
  • D 8
Solution:
2028 Upvotes Verified Answer
The correct answer is: 4
As the person having tuning fork is moving towards a wall, therefore,
$\begin{array}{ll} & v_{s}=v_{0}=2 \mathrm{~m} / \mathrm{s} \text { (given) } \\ \text { So, } & \frac{f^{\prime}}{f}=\frac{v+v_{0}}{v-v_{0}} \\ \Rightarrow & \frac{f^{\prime}-f}{f}=\frac{v+v_{0}-v+v_{0}}{v-v_{0}} \\ \Rightarrow & \frac{\Delta f}{f}=\frac{2 v_{0}}{v-v_{0}} \\ \text { or } & \Delta f=\frac{2 v_{0}}{v-v_{0}} \times f=\frac{2 \times 2 \times 338}{(340-2)}=4\end{array}$

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