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Question: Answered & Verified by Expert
A photon of energy 10.2 eV corresponds to light of wavelength λ0. Due to an electron transition from n=2 to n=1 in a hydrogen atom, the light of wavelength λ is emitted. If we take into account the recoil of the atom when the photon is emitted, then
PhysicsDual Nature of MatterJEE Main
Options:
  • A λ<λ0
  • B λ>λ0
  • C λ=λ0
  • D None of these
Solution:
1398 Upvotes Verified Answer
The correct answer is: λ>λ0
Without recoil of the atom, the entire energy is carried away by the photon.

hcλ0=10.2 eV

With recoil of the atom, energy is shared between photon and atom. So, the energy of the photon is less, hence its wavelength is more.

hcλ<hcλ0

λ0<λ

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