A pipe closed at one end has length 83 cm . The number of possible natural oscillations of air column whose frequencies lie below 1000 Hz are (velocity of sound in air = 332 m s - 1 )

Question

A pipe closed at one end has length 83 cm . The number of possible natural oscillations of air column whose frequencies lie below 1000 Hz are (velocity of sound in air = 332 m s - 1 ), 3, 4, 5, 6

MARKS App · Accepted Answer

Fundamental frequency n = V 4 L = 332 4 × 83 × 10 − 2 = 100 . Hence possible frequencies are n = 100 . n 1 = 300 . n 2 = 500 . n 3 = 700. n 5 = 900 .

Search any question & find its solution

Looking for more such questions to practice?