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A pipe having an internal diameter $D$ is connected to another pipe of same size. Water flows into the second pipe through ' $n$ ' holes, each of diameter $d$. If the water in the first pipe has speed $v$, the specd of water leaving the second pipe is
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The correct answer is:
$\frac{D^2 v}{n d^2}$
$\pi\left(\frac{D}{2}\right)^2 X v=n\left(\frac{d}{2}\right)^2 X v^{\prime}, \quad v^{\prime}=\frac{D^2 v}{n d^2}$
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