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A plane electromagnetic wave of frequency $20 \mathrm{MHz}$ travels through a space along $x$-direction. If the electric field vector at a certain point in space is $6 \mathrm{Vm}^{-1}$, then what is the magnetic field vector at that point?
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Verified Answer
The correct answer is:
$2 \times 10^{-8} \mathrm{~T}$
Magnetic field,
$\begin{gathered}
B=\frac{E}{c} \text {, where } c=3 \times 10^8 \mathrm{~m} / \mathrm{s} . \\
B=\frac{6}{3 \times 10^8}=2 \times 10^{-8} \mathrm{~T}
\end{gathered}$
$\begin{gathered}
B=\frac{E}{c} \text {, where } c=3 \times 10^8 \mathrm{~m} / \mathrm{s} . \\
B=\frac{6}{3 \times 10^8}=2 \times 10^{-8} \mathrm{~T}
\end{gathered}$
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