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A plane electromagnetic wave of frequency $50 \mathrm{MHz}$ travels in free space. If the average energy densities in the electric field and magnetic field are $\mathrm{K}_{\mathrm{E}}$ and $\mathrm{K}_{\mathrm{B}}$ respectively, then the correct option in the following is
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The correct answer is:
$\mathrm{K}_{\mathrm{E}}=\mathrm{K}_{\mathrm{B}}$
$\mathrm{K}_{\mathrm{E}}=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2=\frac{1}{2} \varepsilon_0 \mathrm{~B}_0^2 \mathrm{C}^2$
$=\frac{1}{2} \varepsilon_0 B_0^2 \times \frac{1}{\mu_0 \varepsilon_0}=\frac{B_0^2}{2 \mu_0}=K_B$
$=\frac{1}{2} \varepsilon_0 B_0^2 \times \frac{1}{\mu_0 \varepsilon_0}=\frac{B_0^2}{2 \mu_0}=K_B$
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