Given,

$\mathrm{A}=25 {\mathrm{m}}^2$     [area of each wing]

${\mathrm{v}}_1=\text{180}\times \frac{5}{\text{18}} \mathrm{m} {\mathrm{s}}^{-1}={\text{50 m s}}^{-1}$     [speed of the air above the wing]

${\mathrm{v}}_2=\text{144}\times \frac{5}{\text{18}} \mathrm{m} {\mathrm{s}}^{-1}=4\text{0 }\mathrm{m} {\mathrm{s}}^{-1}$     [speed of the air below the wing]

According to Bernoulli's theorem

${\mathrm{P}}_1+\frac{1}{2}{\text{ρ}}_{\mathrm{air}}{\text{v}}_1^2={\mathrm{P}}_2+\frac{1}{2}{\text{ρv}}_2^2$

${\text{⇒P}}_2-{\mathrm{P}}_1=\frac{1}{2}{\text{ρ}}_{\mathrm{air}}\left({\text{v}}_1^2-{\text{v}}_2^2\right)$

$\Rightarrow {\mathrm{P}}_1-{\mathrm{P}}_2=\frac{1}{2}\times 1\times \left({50}^2-{40}^2\right)$

$\Rightarrow ∆\mathrm{P}=450 \mathrm{Pa}$

The lifting force acting on the plane is

$∆\mathrm{P}\times {\mathrm{A}}_{\mathrm{total}}=450\times 50 \mathrm{N}=22500 \mathrm{N}$

$\mathrm{Mg}=∆\mathrm{P}\times {\mathrm{A}}_{\mathrm{total}}$

$\Rightarrow \mathrm{M}=2250 \mathrm{kg}$