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Question: Answered & Verified by Expert
A plane P passes through the point 1,1,1 and is parallel to the vectors a=-i^+j^ and b=i^-k^. The distance of the point 332,33,3 from the plane is equal to
MathematicsThree Dimensional GeometryJEE Main
Options:
  • A 3 units
  • B 92 units
  • C 33 units
  • D 3 units
Solution:
1393 Upvotes Verified Answer
The correct answer is: 92 units
Equation of the plane is x-1y-1z-1-11010-1=0
x-1-1-y-11+z-1-1=0
x+y+z-3=0
The distance of point 332,33,3 from x+y+z-3=0 is
332+33+3-33=92 units

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