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A plane wavefront is incident on a water surface at an angle of incidence $60^{\circ}$ then it gets refracted at $45^{\circ} .$ The ratio of width of incident wavefront to that of refracted
wavefront will be $\left[\sin \frac{\pi}{4}=\cos \frac{\pi}{4}=\frac{1}{\sqrt{2}}, \sin 60^{\circ}=\frac{\sqrt{3}}{2}, \cos 60^{\circ}=\frac{1}{2}\right]$
Options:
wavefront will be $\left[\sin \frac{\pi}{4}=\cos \frac{\pi}{4}=\frac{1}{\sqrt{2}}, \sin 60^{\circ}=\frac{\sqrt{3}}{2}, \cos 60^{\circ}=\frac{1}{2}\right]$
Solution:
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The correct answer is:
$\frac{1}{\sqrt{2}}$
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