A plane wavefront of wavelength $ \lambda $ is incident on a slit of width $ \mathrm{a} $. The angular width of principle maximum is

Question

A plane wavefront of wavelength $ \lambda $ is incident on a slit of width $ \mathrm{a} $. The angular width of principle maximum is, $ \frac{\lambda}{a} $, $ \frac{(2 \lambda)}{a} $, $ \frac{a}{\lambda} $, $ \frac{a}{(2 \lambda)} $

MARKS App · Accepted Answer

Given, wavelength $ =\lambda ; $ width of slit $ =\mathrm{a} . $ Therefore, angular width of central maximum $ 2 \theta=\frac{2 \lambda}{a} $

Search any question & find its solution

Looking for more such questions to practice?