A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km s - 1 , the escape velocity from the surface of the planet would be

Question

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km s - 1 , the escape velocity from the surface of the planet would be, 0 . 11 km s - 1, 1 . 1 km s - 1, 11 km s - 1, 110 km s - 1

MARKS App · Accepted Answer

v escape = 2 GM R for the earth v e = 11 km s - 1 Mass of the planet = 10 M e . Radius of the planet = R 10 . ∴ v e = 2 GM × 1 0 R / 10 = 10 × 11 = 1 1 0 km s - 1

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