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A plant with genotype AABbCcDD is self-pollinated. Provided that the four genes are independently assorting, what proportion of the progeny will show the genotype AAbbccDD?
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Gamete are formed by reductional division having half the chromosomal content of the parent cell. During the meiotic division, crossing over occurs resulting in formation of new combination. For the given genotype the gamete combination will be - ABCD, ABcD, AbcD, AbCD.
Mendel's law of independent assortment states that "the alleles of two (or more) different genes get sorted into gametes independently of one another."
On selfing, the outcome will be
Thus, the genotype AAbbccDD will be expressed in 1/16th of progenies.
Mendel's law of independent assortment states that "the alleles of two (or more) different genes get sorted into gametes independently of one another."
On selfing, the outcome will be
| ABCD | ABcD | AbCD | AbcD | |
| ABCD | AABBCCDD | AABBCcDD | AABbCCDD | AABbCcDD |
| ABcD | AABBCcDD | AABBccDD | AABbCcDD | AABbccDD |
| AbCD | AABbCCDD | AABbCcDD | AAbbCCDD | AAbbCcDD |
| AbcD | AABbCcDD | AABBccDD | AAbbCcDD | AAbbccDD |
Thus, the genotype AAbbccDD will be expressed in 1/16th of progenies.
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