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A player caught a cricket ball of mass $150 \mathrm{~g}$ moving at a rate of $20 \mathrm{~m} / \mathrm{s}$. If the catching process is completed in $0.1 \mathrm{~s}$, the force of the blow exerted by the ball on the hand of the player is equal to
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$30 \mathrm{~N}$
$30 \mathrm{~N}$
$(m v-0) \Rightarrow 0.15 \times 20$
$\mathrm{F}=\frac{3}{0.1}=30 \mathrm{~N}$
$\mathrm{F}=\frac{3}{0.1}=30 \mathrm{~N}$
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